Base | Representation |
---|---|
bin | 1010100101000111100111… |
… | …10010101101100100101011 |
3 | 10001101011122222010222020111 |
4 | 11102203303302231210223 |
5 | 11022141004024014431 |
6 | 121252030111235151 |
7 | 4620613034552653 |
oct | 522436362554453 |
9 | 101334588128214 |
10 | 23265633032491 |
11 | 745a999349723 |
12 | 2739051518ab7 |
13 | cc9c2a9117b5 |
14 | 5a60c3c91363 |
15 | 2a52d4a9d7b1 |
hex | 1528f3cad92b |
23265633032491 has 2 divisors, whose sum is σ = 23265633032492. Its totient is φ = 23265633032490.
The previous prime is 23265633032489. The next prime is 23265633032531. The reversal of 23265633032491 is 19423033656232.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23265633032491 - 21 = 23265633032489 is a prime.
Together with 23265633032489, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (23265633032791) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11632816516245 + 11632816516246.
It is an arithmetic number, because the mean of its divisors is an integer number (11632816516246).
Almost surely, 223265633032491 is an apocalyptic number.
23265633032491 is a deficient number, since it is larger than the sum of its proper divisors (1).
23265633032491 is an equidigital number, since it uses as much as digits as its factorization.
23265633032491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4199040, while the sum is 49.
The spelling of 23265633032491 in words is "twenty-three trillion, two hundred sixty-five billion, six hundred thirty-three million, thirty-two thousand, four hundred ninety-one".
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