Base | Representation |
---|---|
bin | 1010100110001101100111… |
… | …01000001101101001110011 |
3 | 10001111202122212011220200101 |
4 | 11103012303220031221303 |
5 | 11023244434034303042 |
6 | 121321203014533231 |
7 | 4623413204232232 |
oct | 523066350155163 |
9 | 101452585156611 |
10 | 23303211244147 |
11 | 747492226329a |
12 | 274439a367217 |
13 | 1000639019cb3 |
14 | 5a7c4a96ab19 |
15 | 2a6283b586b7 |
hex | 1531b3a0da73 |
23303211244147 has 2 divisors, whose sum is σ = 23303211244148. Its totient is φ = 23303211244146.
The previous prime is 23303211244097. The next prime is 23303211244177. The reversal of 23303211244147 is 74144211230332.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 23303211244147 - 223 = 23303202855539 is a prime.
It is a super-3 number, since 3×233032112441473 (a number of 41 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (23303211244177) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11651605622073 + 11651605622074.
It is an arithmetic number, because the mean of its divisors is an integer number (11651605622074).
Almost surely, 223303211244147 is an apocalyptic number.
23303211244147 is a deficient number, since it is larger than the sum of its proper divisors (1).
23303211244147 is an equidigital number, since it uses as much as digits as its factorization.
23303211244147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96768, while the sum is 37.
Adding to 23303211244147 its reverse (74144211230332), we get a palindrome (97447422474479).
The spelling of 23303211244147 in words is "twenty-three trillion, three hundred three billion, two hundred eleven million, two hundred forty-four thousand, one hundred forty-seven".
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