Base | Representation |
---|---|
bin | 100001111011000001101… |
… | …001011100111001110101 |
3 | 22020212000211200202201102 |
4 | 201323001221130321311 |
5 | 301143114003042123 |
6 | 4542522520135445 |
7 | 330263232533066 |
oct | 41730151347165 |
9 | 8225024622642 |
10 | 2331121143413 |
11 | 819694127817 |
12 | 317953907585 |
13 | 13ba92acc72a |
14 | 80b80cc056d |
15 | 40987926028 |
hex | 21ec1a5ce75 |
2331121143413 has 2 divisors, whose sum is σ = 2331121143414. Its totient is φ = 2331121143412.
The previous prime is 2331121143389. The next prime is 2331121143479. The reversal of 2331121143413 is 3143411211332.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2102711705329 + 228409438084 = 1450073^2 + 477922^2 .
It is a cyclic number.
It is not a de Polignac number, because 2331121143413 - 28 = 2331121143157 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2331121145413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1165560571706 + 1165560571707.
It is an arithmetic number, because the mean of its divisors is an integer number (1165560571707).
Almost surely, 22331121143413 is an apocalyptic number.
It is an amenable number.
2331121143413 is a deficient number, since it is larger than the sum of its proper divisors (1).
2331121143413 is an equidigital number, since it uses as much as digits as its factorization.
2331121143413 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5184, while the sum is 29.
Adding to 2331121143413 its reverse (3143411211332), we get a palindrome (5474532354745).
The spelling of 2331121143413 in words is "two trillion, three hundred thirty-one billion, one hundred twenty-one million, one hundred forty-three thousand, four hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •