Base | Representation |
---|---|
bin | 1010100110011100110111… |
… | …10010011101011000010011 |
3 | 10001112112210122001100200021 |
4 | 11103032123302131120103 |
5 | 11023413222202231121 |
6 | 121325035422204311 |
7 | 4624123152632635 |
oct | 523163362353023 |
9 | 101475718040607 |
10 | 23311401211411 |
11 | 7478345290985 |
12 | 2745aa5123697 |
13 | 1001342a13981 |
14 | 5a83c6564a55 |
15 | 2a65b2b7a641 |
hex | 15339bc9d613 |
23311401211411 has 2 divisors, whose sum is σ = 23311401211412. Its totient is φ = 23311401211410.
The previous prime is 23311401211403. The next prime is 23311401211433. The reversal of 23311401211411 is 11411210411332.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23311401211411 - 23 = 23311401211403 is a prime.
It is a super-2 number, since 2×233114012114112 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (23311401215411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11655700605705 + 11655700605706.
It is an arithmetic number, because the mean of its divisors is an integer number (11655700605706).
Almost surely, 223311401211411 is an apocalyptic number.
23311401211411 is a deficient number, since it is larger than the sum of its proper divisors (1).
23311401211411 is an equidigital number, since it uses as much as digits as its factorization.
23311401211411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 25.
Adding to 23311401211411 its reverse (11411210411332), we get a palindrome (34722611622743).
The spelling of 23311401211411 in words is "twenty-three trillion, three hundred eleven billion, four hundred one million, two hundred eleven thousand, four hundred eleven".
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