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23312112133200 = 24352113121837741
BaseRepresentation
bin1010100110011110001100…
…01010011010010001010000
310001112121122011202221000220
411103033012022122101100
511023421201201230300
6121325234135513040
74624146604443132
oct523170612322120
9101477564687026
1023312112133200
11747867a60aa50
122746063228780
1310014270a8357
145a8452b43052
152a66052a8da0
hex1533c629a450

23312112133200 has 360 divisors, whose sum is σ = 84177963435168. Its totient is φ = 5469114240000.

The previous prime is 23312112133091. The next prime is 23312112133213. The reversal of 23312112133200 is 233121121332.

It is a super-2 number, since 2×233121121332002 (a number of 28 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 11766330 + ... + 13604070.

Almost surely, 223312112133200 is an apocalyptic number.

23312112133200 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 23312112133200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (42088981717584).

23312112133200 is an abundant number, since it is smaller than the sum of its proper divisors (60865851301968).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

23312112133200 is a wasteful number, since it uses less digits than its factorization.

23312112133200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1837835 (or 1837793 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 23312112133200 its reverse (233121121332), we get a palindrome (23545233254532).

23312112133200 divided by its reverse (233121121332) gives a square (100 = 102).

It can be divided in two parts, 233121 and 12133200, that added together give a palindrome (12366321).

The spelling of 23312112133200 in words is "twenty-three trillion, three hundred twelve billion, one hundred twelve million, one hundred thirty-three thousand, two hundred".