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2331213100033 is a prime number
BaseRepresentation
bin100001111011000111001…
…000001111010000000001
322020212021020201122111011
4201323013020033100001
5301143311023200113
64542540003120521
7330265430255146
oct41730710172001
98225236648434
102331213100033
11819731025124
1231797a673141
1313baa8b8812c
1480b8d1ba3cd
1540990a3c63d
hex21ec720f401

2331213100033 has 2 divisors, whose sum is σ = 2331213100034. Its totient is φ = 2331213100032.

The previous prime is 2331213100003. The next prime is 2331213100081. The reversal of 2331213100033 is 3300013121332.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2299384042384 + 31829057649 = 1516372^2 + 178407^2 .

It is a cyclic number.

It is not a de Polignac number, because 2331213100033 - 29 = 2331213099521 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2331213099977 and 2331213100013.

It is not a weakly prime, because it can be changed into another prime (2331213100003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1165606550016 + 1165606550017.

It is an arithmetic number, because the mean of its divisors is an integer number (1165606550017).

Almost surely, 22331213100033 is an apocalyptic number.

It is an amenable number.

2331213100033 is a deficient number, since it is larger than the sum of its proper divisors (1).

2331213100033 is an equidigital number, since it uses as much as digits as its factorization.

2331213100033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 2331213100033 its reverse (3300013121332), we get a palindrome (5631226221365).

The spelling of 2331213100033 in words is "two trillion, three hundred thirty-one billion, two hundred thirteen million, one hundred thousand, thirty-three".