Base | Representation |
---|---|
bin | 1010100110011110001110… |
… | …11010011110010100000011 |
3 | 10001112121200122021020021022 |
4 | 11103033013122132110003 |
5 | 11023421222034340113 |
6 | 121325240205420055 |
7 | 4624150251025646 |
oct | 523170732362403 |
9 | 101477618236238 |
10 | 23312133121283 |
11 | 7478690445676 |
12 | 274606a26a62b |
13 | 100142b546436 |
14 | 5a8455847a5d |
15 | 2a6607052908 |
hex | 1533c769e503 |
23312133121283 has 2 divisors, whose sum is σ = 23312133121284. Its totient is φ = 23312133121282.
The previous prime is 23312133121243. The next prime is 23312133121337. The reversal of 23312133121283 is 38212133121332.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23312133121283 - 28 = 23312133121027 is a prime.
It is not a weakly prime, because it can be changed into another prime (23312133121243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11656066560641 + 11656066560642.
It is an arithmetic number, because the mean of its divisors is an integer number (11656066560642).
Almost surely, 223312133121283 is an apocalyptic number.
23312133121283 is a deficient number, since it is larger than the sum of its proper divisors (1).
23312133121283 is an equidigital number, since it uses as much as digits as its factorization.
23312133121283 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 31104, while the sum is 35.
The spelling of 23312133121283 in words is "twenty-three trillion, three hundred twelve billion, one hundred thirty-three million, one hundred twenty-one thousand, two hundred eighty-three".
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