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23314014441013 is a prime number
BaseRepresentation
bin1010100110100001101111…
…00011001000111000110101
310001112210112202022011202211
411103100313203020320311
511023434100144103023
6121330151012533421
74624245004004062
oct523206743107065
9101483482264684
1023314014441013
1174794663a1a6a
1227464b4321271
13100166b23948a
145a859364bc69
152a66b72c0a0d
hex1534378c8e35

23314014441013 has 2 divisors, whose sum is σ = 23314014441014. Its totient is φ = 23314014441012.

The previous prime is 23314014440929. The next prime is 23314014441019. The reversal of 23314014441013 is 31014441041332.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22775248164964 + 538766276049 = 4772342^2 + 734007^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23314014441013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23314014441019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11657007220506 + 11657007220507.

It is an arithmetic number, because the mean of its divisors is an integer number (11657007220507).

Almost surely, 223314014441013 is an apocalyptic number.

It is an amenable number.

23314014441013 is a deficient number, since it is larger than the sum of its proper divisors (1).

23314014441013 is an equidigital number, since it uses as much as digits as its factorization.

23314014441013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 23314014441013 its reverse (31014441041332), we get a palindrome (54328455482345).

The spelling of 23314014441013 in words is "twenty-three trillion, three hundred fourteen billion, fourteen million, four hundred forty-one thousand, thirteen".