Base | Representation |
---|---|
bin | 110101000000101000110100… |
… | …111101100111111111100100 |
3 | 1010120110222212121001210120102 |
4 | 311000220310331213333210 |
5 | 221024232320123100200 |
6 | 2143503102103323232 |
7 | 100051555024633211 |
oct | 6500506475477744 |
9 | 1116428777053512 |
10 | 233140303331300 |
11 | 6831627a303542 |
12 | 2219419ba50518 |
13 | a0120618b6191 |
14 | 418009d8d4b08 |
15 | 1be47aac496d5 |
hex | d40a34f67fe4 |
233140303331300 has 18 divisors (see below), whose sum is σ = 505914458229138. Its totient is φ = 93256121332480.
The previous prime is 233140303331291. The next prime is 233140303331317. The reversal of 233140303331300 is 3133303041332.
It can be written as a sum of positive squares in 3 ways, for example, as 257259955264 + 232883043376036 = 507208^2 + 15260506^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1165701516557 + ... + 1165701516756.
Almost surely, 2233140303331300 is an apocalyptic number.
233140303331300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
233140303331300 is an abundant number, since it is smaller than the sum of its proper divisors (272774154897838).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
233140303331300 is a wasteful number, since it uses less digits than its factorization.
233140303331300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2331403033327 (or 2331403033320 counting only the distinct ones).
The product of its (nonzero) digits is 17496, while the sum is 29.
Adding to 233140303331300 its reverse (3133303041332), we get a palindrome (236273606372632).
The spelling of 233140303331300 in words is "two hundred thirty-three trillion, one hundred forty billion, three hundred three million, three hundred thirty-one thousand, three hundred".
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