Base | Representation |
---|---|
bin | 100001111011010010110… |
… | …111110110010110011011 |
3 | 22020212202222110211020121 |
4 | 201323102313312112123 |
5 | 301144211443132311 |
6 | 4543011322134111 |
7 | 330303342063412 |
oct | 41732267662633 |
9 | 8225688424217 |
10 | 2331410130331 |
11 | 819822269987 |
12 | 317a14651337 |
13 | 13bb0a9427c9 |
14 | 80bab428479 |
15 | 409a2eabb71 |
hex | 21ed2df659b |
2331410130331 has 2 divisors, whose sum is σ = 2331410130332. Its totient is φ = 2331410130330.
The previous prime is 2331410130319. The next prime is 2331410130337. The reversal of 2331410130331 is 1330310141332.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2331410130331 - 215 = 2331410097563 is a prime.
It is a super-2 number, since 2×23314101303312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2331410130296 and 2331410130305.
It is not a weakly prime, because it can be changed into another prime (2331410130337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1165705065165 + 1165705065166.
It is an arithmetic number, because the mean of its divisors is an integer number (1165705065166).
Almost surely, 22331410130331 is an apocalyptic number.
2331410130331 is a deficient number, since it is larger than the sum of its proper divisors (1).
2331410130331 is an equidigital number, since it uses as much as digits as its factorization.
2331410130331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 2331410130331 its reverse (1330310141332), we get a palindrome (3661720271663).
The spelling of 2331410130331 in words is "two trillion, three hundred thirty-one billion, four hundred ten million, one hundred thirty thousand, three hundred thirty-one".
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