Base | Representation |
---|---|
bin | 100001111011100100001… |
… | …011001001000000000011 |
3 | 22020220112012200001112221 |
4 | 201323210023021000003 |
5 | 301200310300301011 |
6 | 4543100211431511 |
7 | 330313465246144 |
oct | 41734413110003 |
9 | 8226465601487 |
10 | 2331700400131 |
11 | 8199610a7983 |
12 | 317a958b5597 |
13 | 13bb55b1479b |
14 | 80bd7bc7acb |
15 | 409bd6e7971 |
hex | 21ee42c9003 |
2331700400131 has 2 divisors, whose sum is σ = 2331700400132. Its totient is φ = 2331700400130.
The previous prime is 2331700400123. The next prime is 2331700400191. The reversal of 2331700400131 is 1310040071332.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2331700400131 - 23 = 2331700400123 is a prime.
It is a super-2 number, since 2×23317004001312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2331700400096 and 2331700400105.
It is not a weakly prime, because it can be changed into another prime (2331700400101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1165850200065 + 1165850200066.
It is an arithmetic number, because the mean of its divisors is an integer number (1165850200066).
Almost surely, 22331700400131 is an apocalyptic number.
2331700400131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2331700400131 is an equidigital number, since it uses as much as digits as its factorization.
2331700400131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 2331700400131 its reverse (1310040071332), we get a palindrome (3641740471463).
The spelling of 2331700400131 in words is "two trillion, three hundred thirty-one billion, seven hundred million, four hundred thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.107 sec. • engine limits •