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2331941894497 is a prime number
BaseRepresentation
bin100001111011110010100…
…100010111100101100001
322020221011001002020112201
4201323302210113211201
5301201304111110442
64543140155453201
7330322460024305
oct41736244274541
98227131066481
102331941894497
11819a754511a6
12317b42757201
1313bb93b69867
1480c1bccbd05
15409d49eb7b7
hex21ef2917961

2331941894497 has 2 divisors, whose sum is σ = 2331941894498. Its totient is φ = 2331941894496.

The previous prime is 2331941894479. The next prime is 2331941894551. The reversal of 2331941894497 is 7944981491332.

2331941894497 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (2331941894479) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2329558111521 + 2383782976 = 1526289^2 + 48824^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2331941894497 is a prime.

It is not a weakly prime, because it can be changed into another prime (2331941895497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1165970947248 + 1165970947249.

It is an arithmetic number, because the mean of its divisors is an integer number (1165970947249).

Almost surely, 22331941894497 is an apocalyptic number.

It is an amenable number.

2331941894497 is a deficient number, since it is larger than the sum of its proper divisors (1).

2331941894497 is an equidigital number, since it uses as much as digits as its factorization.

2331941894497 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 47029248, while the sum is 64.

The spelling of 2331941894497 in words is "two trillion, three hundred thirty-one billion, nine hundred forty-one million, eight hundred ninety-four thousand, four hundred ninety-seven".