Base | Representation |
---|---|
bin | 1010100110101101010010… |
… | …11111101100111100011111 |
3 | 10001120101120022020122001201 |
4 | 11103112221133230330133 |
5 | 11024034303101010142 |
6 | 121333054531220331 |
7 | 4624554550554061 |
oct | 523265137547437 |
9 | 101511508218051 |
10 | 23320221110047 |
11 | 7481060950304 |
12 | 2747746a476a7 |
13 | 100211a085bc4 |
14 | 5a89c1a97731 |
15 | 2a692c12dab7 |
hex | 1535a97ecf1f |
23320221110047 has 2 divisors, whose sum is σ = 23320221110048. Its totient is φ = 23320221110046.
The previous prime is 23320221109957. The next prime is 23320221110089. The reversal of 23320221110047 is 74001112202332.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-23320221110047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23320221109997 and 23320221110024.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23320221117047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11660110555023 + 11660110555024.
It is an arithmetic number, because the mean of its divisors is an integer number (11660110555024).
Almost surely, 223320221110047 is an apocalyptic number.
23320221110047 is a deficient number, since it is larger than the sum of its proper divisors (1).
23320221110047 is an equidigital number, since it uses as much as digits as its factorization.
23320221110047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 23320221110047 its reverse (74001112202332), we get a palindrome (97321333312379).
The spelling of 23320221110047 in words is "twenty-three trillion, three hundred twenty billion, two hundred twenty-one million, one hundred ten thousand, forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •