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2332153245041 is a prime number
BaseRepresentation
bin100001111011111111001…
…010100110110101110001
322020221200202202221222122
4201323333022212311301
5301202222212320131
64543213145444025
7330330634334534
oct41737712466561
98227622687878
102332153245041
1181a073786a74
12317ba14a0615
1313bbc8899359
1480c3bdc6a1b
15409e8348d7b
hex21eff2a6d71

2332153245041 has 2 divisors, whose sum is σ = 2332153245042. Its totient is φ = 2332153245040.

The previous prime is 2332153245029. The next prime is 2332153245053. The reversal of 2332153245041 is 1405423512332.

It is a balanced prime because it is at equal distance from previous prime (2332153245029) and next prime (2332153245053).

It can be written as a sum of positive squares in only one way, i.e., 1873175449600 + 458977795441 = 1368640^2 + 677479^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2332153245041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2332153244992 and 2332153245010.

It is not a weakly prime, because it can be changed into another prime (2332153245001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1166076622520 + 1166076622521.

It is an arithmetic number, because the mean of its divisors is an integer number (1166076622521).

Almost surely, 22332153245041 is an apocalyptic number.

It is an amenable number.

2332153245041 is a deficient number, since it is larger than the sum of its proper divisors (1).

2332153245041 is an equidigital number, since it uses as much as digits as its factorization.

2332153245041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 2332153245041 its reverse (1405423512332), we get a palindrome (3737576757373).

The spelling of 2332153245041 in words is "two trillion, three hundred thirty-two billion, one hundred fifty-three million, two hundred forty-five thousand, forty-one".