Base | Representation |
---|---|
bin | 100001111100000011110… |
… | …100011110110101001011 |
3 | 22020221220012201010222122 |
4 | 201330003310132311023 |
5 | 301202402210044042 |
6 | 4543225015241455 |
7 | 330332603140034 |
oct | 41740364366513 |
9 | 8227805633878 |
10 | 2332231331147 |
11 | 81a103870243 |
12 | 31800367928b |
13 | 13bc0bb09553 |
14 | 80c48511a8b |
15 | 40a001207d2 |
hex | 21f03d1ed4b |
2332231331147 has 2 divisors, whose sum is σ = 2332231331148. Its totient is φ = 2332231331146.
The previous prime is 2332231331071. The next prime is 2332231331149. The reversal of 2332231331147 is 7411331322332.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2332231331147 is a prime.
Together with 2332231331149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2332231331149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1166115665573 + 1166115665574.
It is an arithmetic number, because the mean of its divisors is an integer number (1166115665574).
Almost surely, 22332231331147 is an apocalyptic number.
2332231331147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2332231331147 is an equidigital number, since it uses as much as digits as its factorization.
2332231331147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 54432, while the sum is 35.
Adding to 2332231331147 its reverse (7411331322332), we get a palindrome (9743562653479).
The spelling of 2332231331147 in words is "two trillion, three hundred thirty-two billion, two hundred thirty-one million, three hundred thirty-one thousand, one hundred forty-seven".
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