Base | Representation |
---|---|
bin | 110101000011001010100110… |
… | …111100100000010010010110 |
3 | 1010121002121020210221221201002 |
4 | 311003022212330200102112 |
5 | 221040104100132111204 |
6 | 2144114551205103302 |
7 | 100100244530033435 |
oct | 6503124674402226 |
9 | 1117077223857632 |
10 | 233314014332054 |
11 | 68382a10674487 |
12 | 2220199b3b7b32 |
13 | a0255566160a6 |
14 | 418865c37311c |
15 | 1be907628091e |
hex | d432a6f20496 |
233314014332054 has 4 divisors (see below), whose sum is σ = 349971021498084. Its totient is φ = 116657007166026.
The previous prime is 233314014332053. The next prime is 233314014332083. The reversal of 233314014332054 is 450233410413332.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 233314014331999 and 233314014332017.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (233314014332053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58328503583012 + ... + 58328503583015.
It is an arithmetic number, because the mean of its divisors is an integer number (87492755374521).
Almost surely, 2233314014332054 is an apocalyptic number.
233314014332054 is a deficient number, since it is larger than the sum of its proper divisors (116657007166030).
233314014332054 is a wasteful number, since it uses less digits than its factorization.
233314014332054 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 116657007166029.
The product of its (nonzero) digits is 311040, while the sum is 38.
Adding to 233314014332054 its reverse (450233410413332), we get a palindrome (683547424745386).
The spelling of 233314014332054 in words is "two hundred thirty-three trillion, three hundred fourteen billion, fourteen million, three hundred thirty-two thousand, fifty-four".
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