Base | Representation |
---|---|
bin | 11011110100110… |
… | …01011101010001 |
3 | 121021012120122221 |
4 | 31322121131101 |
5 | 434223144213 |
6 | 35054501041 |
7 | 5532654502 |
oct | 1572313521 |
9 | 537176587 |
10 | 233412433 |
11 | 10a834241 |
12 | 66204781 |
13 | 39485587 |
14 | 22ddcba9 |
15 | 1575938d |
hex | de99751 |
233412433 has 2 divisors, whose sum is σ = 233412434. Its totient is φ = 233412432.
The previous prime is 233412427. The next prime is 233412469. The reversal of 233412433 is 334214332.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 119093569 + 114318864 = 10913^2 + 10692^2 .
It is a cyclic number.
It is not a de Polignac number, because 233412433 - 25 = 233412401 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 233412398 and 233412407.
It is not a weakly prime, because it can be changed into another prime (233412493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116706216 + 116706217.
It is an arithmetic number, because the mean of its divisors is an integer number (116706217).
Almost surely, 2233412433 is an apocalyptic number.
It is an amenable number.
233412433 is a deficient number, since it is larger than the sum of its proper divisors (1).
233412433 is an equidigital number, since it uses as much as digits as its factorization.
233412433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5184, while the sum is 25.
The square root of 233412433 is about 15277.8412414843. The cubic root of 233412433 is about 615.7078091188.
Adding to 233412433 its reverse (334214332), we get a palindrome (567626765).
The spelling of 233412433 in words is "two hundred thirty-three million, four hundred twelve thousand, four hundred thirty-three".
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