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23351111123147 is a prime number
BaseRepresentation
bin1010100111100110110101…
…01011110000000011001011
310001200100022002020212212222
411103303122223300003023
511030041033421420042
6121355204035324255
74630030205415233
oct523633253600313
9101610262225788
1023351111123147
117493172515355
122751727a5068b
131005000958a72
145aa2b23bccc3
152a7638e602d2
hex153cdaaf00cb

23351111123147 has 2 divisors, whose sum is σ = 23351111123148. Its totient is φ = 23351111123146.

The previous prime is 23351111123101. The next prime is 23351111123149. The reversal of 23351111123147 is 74132111115332.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 23351111123147 - 26 = 23351111123083 is a prime.

Together with 23351111123149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (23351111123149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11675555561573 + 11675555561574.

It is an arithmetic number, because the mean of its divisors is an integer number (11675555561574).

Almost surely, 223351111123147 is an apocalyptic number.

23351111123147 is a deficient number, since it is larger than the sum of its proper divisors (1).

23351111123147 is an equidigital number, since it uses as much as digits as its factorization.

23351111123147 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 15120, while the sum is 35.

Adding to 23351111123147 its reverse (74132111115332), we get a palindrome (97483222238479).

The spelling of 23351111123147 in words is "twenty-three trillion, three hundred fifty-one billion, one hundred eleven million, one hundred twenty-three thousand, one hundred forty-seven".