23364334334051 has 2 divisors, whose sum is σ = 23364334334052. Its totient is φ = 23364334334050.

The previous prime is 23364334333993. The next prime is 23364334334053. The reversal of 23364334334051 is 15043343346332.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-23364334334051 is a prime.

Together with 23364334334053, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 23364334333993 and 23364334334011.

It is not a weakly prime, because it can be changed into another prime (23364334334053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11682167167025 + 11682167167026.

It is an arithmetic number, because the mean of its divisors is an integer number (11682167167026).

Almost surely, 2^{23364334334051} is an apocalyptic number.

23364334334051 is a deficient number, since it is larger than the sum of its proper divisors (1).

23364334334051 is an equidigital number, since it uses as much as digits as its factorization.

23364334334051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2799360, while the sum is 44.

The spelling of 23364334334051 in words is "twenty-three trillion, three hundred sixty-four billion, three hundred thirty-four million, three hundred thirty-four thousand, fifty-one".