Base | Representation |
---|---|
bin | 1010101001000011110100… |
… | …01100111011111111100111 |
3 | 10001212010011011021020102001 |
4 | 11110201322030323333213 |
5 | 11031400303200243143 |
6 | 121434141414030131 |
7 | 4633445250255142 |
oct | 524417214737747 |
9 | 101763134236361 |
10 | 23401032040423 |
11 | 750235a583384 |
12 | 275b33a348347 |
13 | 10099281c9a7b |
14 | 5ac88a405059 |
15 | 2a8aab8d314d |
hex | 15487a33bfe7 |
23401032040423 has 2 divisors, whose sum is σ = 23401032040424. Its totient is φ = 23401032040422.
The previous prime is 23401032040363. The next prime is 23401032040537. The reversal of 23401032040423 is 32404023010432.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23401032040423 - 217 = 23401031909351 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23401032040391 and 23401032040400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23401032041423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11700516020211 + 11700516020212.
It is an arithmetic number, because the mean of its divisors is an integer number (11700516020212).
Almost surely, 223401032040423 is an apocalyptic number.
23401032040423 is a deficient number, since it is larger than the sum of its proper divisors (1).
23401032040423 is an equidigital number, since it uses as much as digits as its factorization.
23401032040423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 28.
Adding to 23401032040423 its reverse (32404023010432), we get a palindrome (55805055050855).
The spelling of 23401032040423 in words is "twenty-three trillion, four hundred one billion, thirty-two million, forty thousand, four hundred twenty-three".
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