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2340110431411 is a prime number
BaseRepresentation
bin100010000011011001011…
…100110111010010110011
322021201020022121220121221
4202003121130313102303
5301320021232301121
64551010515525511
7331032055320604
oct42033134672263
98251208556557
102340110431411
11822487371955
123196422b9897
1313c89629c05c
1481394b07dab
1540d11bd8b41
hex220d97374b3

2340110431411 has 2 divisors, whose sum is σ = 2340110431412. Its totient is φ = 2340110431410.

The previous prime is 2340110431369. The next prime is 2340110431487. The reversal of 2340110431411 is 1141340110432.

2340110431411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2340110431411 - 219 = 2340109907123 is a prime.

It is a super-2 number, since 2×23401104314112 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2340110431511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1170055215705 + 1170055215706.

It is an arithmetic number, because the mean of its divisors is an integer number (1170055215706).

Almost surely, 22340110431411 is an apocalyptic number.

2340110431411 is a deficient number, since it is larger than the sum of its proper divisors (1).

2340110431411 is an equidigital number, since it uses as much as digits as its factorization.

2340110431411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 2340110431411 its reverse (1141340110432), we get a palindrome (3481450541843).

The spelling of 2340110431411 in words is "two trillion, three hundred forty billion, one hundred ten million, four hundred thirty-one thousand, four hundred eleven".