Base | Representation |
---|---|
bin | 10101110010110100… |
… | …100010010011011111 |
3 | 2020101212111200202100 |
4 | 111302310202103133 |
5 | 340411202223403 |
6 | 14430025100143 |
7 | 1455622004154 |
oct | 256264422337 |
9 | 66355450670 |
10 | 23401211103 |
11 | 9a19412296 |
12 | 4651027653 |
13 | 228c235a9a |
14 | 11bdcca22b |
15 | 91e6622a3 |
hex | 572d224df |
23401211103 has 48 divisors (see below), whose sum is σ = 35710811136. Its totient is φ = 14737282560.
The previous prime is 23401211051. The next prime is 23401211131. The reversal of 23401211103 is 30111210432.
It is not a de Polignac number, because 23401211103 - 212 = 23401207007 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (23401211003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 12668926 + ... + 12670772.
It is an arithmetic number, because the mean of its divisors is an integer number (743975232).
Almost surely, 223401211103 is an apocalyptic number.
23401211103 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
23401211103 is a deficient number, since it is larger than the sum of its proper divisors (12309600033).
23401211103 is a wasteful number, since it uses less digits than its factorization.
23401211103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2604 (or 2601 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 23401211103 its reverse (30111210432), we get a palindrome (53512421535).
The spelling of 23401211103 in words is "twenty-three billion, four hundred one million, two hundred eleven thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •