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23401810433 is a prime number
BaseRepresentation
bin10101110010110110…
…110100101000000001
32020101220122010212202
4111302312310220001
5340411330413213
614430050002545
71455630051401
oct256266645001
966356563782
1023401810433
119a19791601
124651276455
13228c3b5811
1411c0004801
1591e72eb58
hex572db4a01

23401810433 has 2 divisors, whose sum is σ = 23401810434. Its totient is φ = 23401810432.

The previous prime is 23401810423. The next prime is 23401810447. The reversal of 23401810433 is 33401810432.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22342177729 + 1059632704 = 149473^2 + 32552^2 .

It is a cyclic number.

It is not a de Polignac number, because 23401810433 - 216 = 23401744897 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 23401810396 and 23401810405.

It is not a weakly prime, because it can be changed into another prime (23401810403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11700905216 + 11700905217.

It is an arithmetic number, because the mean of its divisors is an integer number (11700905217).

Almost surely, 223401810433 is an apocalyptic number.

It is an amenable number.

23401810433 is a deficient number, since it is larger than the sum of its proper divisors (1).

23401810433 is an equidigital number, since it uses as much as digits as its factorization.

23401810433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Subtracting 23401810433 from its reverse (33401810432), we obtain a palindrome (9999999999).

The spelling of 23401810433 in words is "twenty-three billion, four hundred one million, eight hundred ten thousand, four hundred thirty-three".