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2340213433 is a prime number
BaseRepresentation
bin1000101101111100…
…1101001010111001
320001002112011022121
42023133031022321
514243043312213
61024114521241
7111664325455
oct21337151271
96032464277
102340213433
11aa0a97a98
12553896221
132b3ab4b9c
14182b39665
15da6b688d
hex8b7cd2b9

2340213433 has 2 divisors, whose sum is σ = 2340213434. Its totient is φ = 2340213432.

The previous prime is 2340213427. The next prime is 2340213581. The reversal of 2340213433 is 3343120432.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1707590329 + 632623104 = 41323^2 + 25152^2 .

It is a cyclic number.

It is not a de Polignac number, because 2340213433 - 29 = 2340212921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2340213398 and 2340213407.

It is not a weakly prime, because it can be changed into another prime (2340213133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1170106716 + 1170106717.

It is an arithmetic number, because the mean of its divisors is an integer number (1170106717).

Almost surely, 22340213433 is an apocalyptic number.

It is an amenable number.

2340213433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2340213433 is an equidigital number, since it uses as much as digits as its factorization.

2340213433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 25.

The square root of 2340213433 is about 48375.7525316144. The cubic root of 2340213433 is about 1327.6547572402.

Adding to 2340213433 its reverse (3343120432), we get a palindrome (5683333865).

The spelling of 2340213433 in words is "two billion, three hundred forty million, two hundred thirteen thousand, four hundred thirty-three".