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2340232413433 is a prime number
BaseRepresentation
bin100010000011100000101…
…110001100000011111001
322021201112211011020111121
4202003200232030003321
5301320243444212213
64551030554225241
7331035066205405
oct42034056140371
98251484136447
102340232413433
1182253a207842
12319677125221
1313c8b563b175
14813a6dbc105
1540d1c78188d
hex220e0b8c0f9

2340232413433 has 2 divisors, whose sum is σ = 2340232413434. Its totient is φ = 2340232413432.

The previous prime is 2340232413413. The next prime is 2340232413457. The reversal of 2340232413433 is 3343142320432.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2296946362624 + 43286050809 = 1515568^2 + 208053^2 .

It is a cyclic number.

It is not a de Polignac number, because 2340232413433 - 25 = 2340232413401 is a prime.

It is not a weakly prime, because it can be changed into another prime (2340232413413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1170116206716 + 1170116206717.

It is an arithmetic number, because the mean of its divisors is an integer number (1170116206717).

Almost surely, 22340232413433 is an apocalyptic number.

It is an amenable number.

2340232413433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2340232413433 is an equidigital number, since it uses as much as digits as its factorization.

2340232413433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 124416, while the sum is 34.

Adding to 2340232413433 its reverse (3343142320432), we get a palindrome (5683374733865).

The spelling of 2340232413433 in words is "two trillion, three hundred forty billion, two hundred thirty-two million, four hundred thirteen thousand, four hundred thirty-three".