Base | Representation |
---|---|
bin | 1101100111110110000… |
… | …0111110101000011011 |
3 | 211101002020022121020221 |
4 | 3121331200332220123 |
5 | 12313300202444011 |
6 | 255302545300511 |
7 | 22623403304365 |
oct | 3317540765033 |
9 | 741066277227 |
10 | 234034031131 |
11 | 9028712255a |
12 | 39435634737 |
13 | 190b938c734 |
14 | b4821bbd35 |
15 | 614b2e6971 |
hex | 367d83ea1b |
234034031131 has 2 divisors, whose sum is σ = 234034031132. Its totient is φ = 234034031130.
The previous prime is 234034031117. The next prime is 234034031207. The reversal of 234034031131 is 131130430432.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 234034031131 - 27 = 234034031003 is a prime.
It is a super-2 number, since 2×2340340311312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 234034031096 and 234034031105.
It is not a weakly prime, because it can be changed into another prime (234034031531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 117017015565 + 117017015566.
It is an arithmetic number, because the mean of its divisors is an integer number (117017015566).
Almost surely, 2234034031131 is an apocalyptic number.
234034031131 is a deficient number, since it is larger than the sum of its proper divisors (1).
234034031131 is an equidigital number, since it uses as much as digits as its factorization.
234034031131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 234034031131 its reverse (131130430432), we get a palindrome (365164461563).
The spelling of 234034031131 in words is "two hundred thirty-four billion, thirty-four million, thirty-one thousand, one hundred thirty-one".
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