234042433 has 2 divisors, whose sum is σ = 234042434. Its totient is φ = 234042432.

The previous prime is 234042401. The next prime is 234042449. The reversal of 234042433 is 334240432.

234042433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 179104689 + 54937744 = 13383^2 + 7412^2 .

It is a cyclic number.

It is not a de Polignac number, because 234042433 - 2⁵ = 234042401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 234042398 and 234042407.

It is not a weakly prime, because it can be changed into another prime (234042463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 117021216 + 117021217.

It is an arithmetic number, because the mean of its divisors is an integer number (117021217).

Almost surely, 2^234042433 is an apocalyptic number.

It is an amenable number.

234042433 is a deficient number, since it is larger than the sum of its proper divisors (1).

234042433 is an equidigital number, since it uses as much as digits as its factorization.

234042433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 25.

The square root of 234042433 is about 15298.4454439005. The cubic root of 234042433 is about 616.2612607197.

Adding to 234042433 its reverse (334240432), we get a palindrome (568282865).

The spelling of 234042433 in words is "two hundred thirty-four million, forty-two thousand, four hundred thirty-three".