Base | Representation |
---|---|
bin | 1010101001110011010100… |
… | …10100100101010101110111 |
3 | 10001221112222112100210201212 |
4 | 11110321222110211111313 |
5 | 11032310021031204421 |
6 | 121454000215512035 |
7 | 4635340246331315 |
oct | 524715224452567 |
9 | 101845875323655 |
10 | 23426535413111 |
11 | 751215756a796 |
12 | 276427738861b |
13 | 100c160ac953c |
14 | 5adbc95810b5 |
15 | 2a95a0887e5b |
hex | 154e6a525577 |
23426535413111 has 2 divisors, whose sum is σ = 23426535413112. Its totient is φ = 23426535413110.
The previous prime is 23426535413087. The next prime is 23426535413119. The reversal of 23426535413111 is 11131453562432.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 23426535413111 - 238 = 23151657506167 is a prime.
It is a super-2 number, since 2×234265354131112 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23426535413119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11713267706555 + 11713267706556.
It is an arithmetic number, because the mean of its divisors is an integer number (11713267706556).
Almost surely, 223426535413111 is an apocalyptic number.
23426535413111 is a deficient number, since it is larger than the sum of its proper divisors (1).
23426535413111 is an equidigital number, since it uses as much as digits as its factorization.
23426535413111 is an evil number, because the sum of its binary digits is even.
The product of its digits is 259200, while the sum is 41.
Adding to 23426535413111 its reverse (11131453562432), we get a palindrome (34557988975543).
The spelling of 23426535413111 in words is "twenty-three trillion, four hundred twenty-six billion, five hundred thirty-five million, four hundred thirteen thousand, one hundred eleven".
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