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23433203433209 is a prime number
BaseRepresentation
bin1010101001111111101111…
…10001000011111011111001
310001222012012020102022201012
411110333313301003323321
511032412200034330314
6121501022014403305
74635664424505203
oct524776761037371
9101865166368635
1023433203433209
117514a694879a9
122765618500535
13100c9843b846b
145b025cda1773
152a9840e7793e
hex154ff7c43ef9

23433203433209 has 2 divisors, whose sum is σ = 23433203433210. Its totient is φ = 23433203433208.

The previous prime is 23433203433161. The next prime is 23433203433257. The reversal of 23433203433209 is 90233430233432.

It is a balanced prime because it is at equal distance from previous prime (23433203433161) and next prime (23433203433257).

It can be written as a sum of positive squares in only one way, i.e., 17180428125184 + 6252775308025 = 4144928^2 + 2500555^2 .

It is a cyclic number.

It is not a de Polignac number, because 23433203433209 - 224 = 23433186655993 is a prime.

It is not a weakly prime, because it can be changed into another prime (23433203435209) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11716601716604 + 11716601716605.

It is an arithmetic number, because the mean of its divisors is an integer number (11716601716605).

Almost surely, 223433203433209 is an apocalyptic number.

It is an amenable number.

23433203433209 is a deficient number, since it is larger than the sum of its proper divisors (1).

23433203433209 is an equidigital number, since it uses as much as digits as its factorization.

23433203433209 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 839808, while the sum is 41.

The spelling of 23433203433209 in words is "twenty-three trillion, four hundred thirty-three billion, two hundred three million, four hundred thirty-three thousand, two hundred nine".