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2343340333112 = 231223239507393
BaseRepresentation
bin100010000110011001111…
…101111101100000111000
322022000120102020220210212
4202012121331331200320
5301343130111124422
64552303215530252
7331205105116622
oct42063175754070
98260512226725
102343340333112
118238945888a9
1231a1a3b29988
1313cc8c4a9bac
14815bda77c12
1540e505419e2
hex22199f7d838

2343340333112 has 16 divisors (see below), whose sum is σ = 4397355753840. Its totient is φ = 1170712132096.

The previous prime is 2343340333109. The next prime is 2343340333123. The reversal of 2343340333112 is 2113330433432.

2343340333112 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-3 number, since 3×23433403331123 (a number of 38 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 119743913 + ... + 119763480.

It is an arithmetic number, because the mean of its divisors is an integer number (274834734615).

Almost surely, 22343340333112 is an apocalyptic number.

It is an amenable number.

2343340333112 is a deficient number, since it is larger than the sum of its proper divisors (2054015420728).

2343340333112 is a wasteful number, since it uses less digits than its factorization.

2343340333112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 239508622 (or 239508618 counting only the distinct ones).

The product of its (nonzero) digits is 46656, while the sum is 32.

Adding to 2343340333112 its reverse (2113330433432), we get a palindrome (4456670766544).

The spelling of 2343340333112 in words is "two trillion, three hundred forty-three billion, three hundred forty million, three hundred thirty-three thousand, one hundred twelve".

Divisors: 1 2 4 8 1223 2446 4892 9784 239507393 479014786 958029572 1916059144 292917541639 585835083278 1171670166556 2343340333112