Base | Representation |
---|---|
bin | 1010101010000010001010… |
… | …00011100000001011111000 |
3 | 10001222022112121100111011222 |
4 | 11111001011003200023320 |
5 | 11032422324012110034 |
6 | 121501354415011212 |
7 | 4636041521220161 |
oct | 525010503401370 |
9 | 101868477314158 |
10 | 23434500113144 |
11 | 751557441780a |
12 | 276591a809b08 |
13 | 100cb2cc301b3 |
14 | 5b034329a768 |
15 | 2a98b9c0e12e |
hex | 1550450e02f8 |
23434500113144 has 8 divisors (see below), whose sum is σ = 43939687712160. Its totient is φ = 11717250056568.
The previous prime is 23434500113137. The next prime is 23434500113191. The reversal of 23434500113144 is 44131100543432.
It is a tau number, because it is divible by the number of its divisors (8).
It is a super-2 number, since 2×234345001131442 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1464656257064 + ... + 1464656257079.
It is an arithmetic number, because the mean of its divisors is an integer number (5492460964020).
Almost surely, 223434500113144 is an apocalyptic number.
It is an amenable number.
23434500113144 is a deficient number, since it is larger than the sum of its proper divisors (20505187599016).
23434500113144 is a wasteful number, since it uses less digits than its factorization.
23434500113144 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2929312514149 (or 2929312514145 counting only the distinct ones).
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 23434500113144 its reverse (44131100543432), we get a palindrome (67565600656576).
The spelling of 23434500113144 in words is "twenty-three trillion, four hundred thirty-four billion, five hundred million, one hundred thirteen thousand, one hundred forty-four".
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