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2344163615113 is a prime number
BaseRepresentation
bin100010000111001011000…
…010100010000110001001
322022002200210101222101211
4202013023002202012021
5301401321341140423
64552521025413121
7331234362651655
oct42071302420611
98262623358354
102344163615113
11824177280851
1231a39379a1a1
13140090c21cc8
148165b143a65
1540e9c96710d
hex221cb0a2189

2344163615113 has 2 divisors, whose sum is σ = 2344163615114. Its totient is φ = 2344163615112.

The previous prime is 2344163615111. The next prime is 2344163615119. The reversal of 2344163615113 is 3115163614432.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1208091153424 + 1136072461689 = 1099132^2 + 1065867^2 .

It is a cyclic number.

It is not a de Polignac number, because 2344163615113 - 21 = 2344163615111 is a prime.

Together with 2344163615111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (2344163615111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1172081807556 + 1172081807557.

It is an arithmetic number, because the mean of its divisors is an integer number (1172081807557).

Almost surely, 22344163615113 is an apocalyptic number.

It is an amenable number.

2344163615113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2344163615113 is an equidigital number, since it uses as much as digits as its factorization.

2344163615113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 155520, while the sum is 40.

The spelling of 2344163615113 in words is "two trillion, three hundred forty-four billion, one hundred sixty-three million, six hundred fifteen thousand, one hundred thirteen".