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23451504133 is a prime number
BaseRepresentation
bin10101110101110100…
…011000111000000101
32020112101010211211011
4111311310120320011
5341012041113013
614435023042221
71460102332111
oct256564307005
966471124734
1023451504133
119a44843182
124665a40371
132299794685
1411c685c741
15923c98c3d
hex575d18e05

23451504133 has 2 divisors, whose sum is σ = 23451504134. Its totient is φ = 23451504132.

The previous prime is 23451504103. The next prime is 23451504137. The reversal of 23451504133 is 33140515432.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22847229409 + 604274724 = 151153^2 + 24582^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23451504133 is a prime.

It is a super-2 number, since 2×234515041332 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 23451504095 and 23451504104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23451504137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11725752066 + 11725752067.

It is an arithmetic number, because the mean of its divisors is an integer number (11725752067).

Almost surely, 223451504133 is an apocalyptic number.

It is an amenable number.

23451504133 is a deficient number, since it is larger than the sum of its proper divisors (1).

23451504133 is an equidigital number, since it uses as much as digits as its factorization.

23451504133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600, while the sum is 31.

The spelling of 23451504133 in words is "twenty-three billion, four hundred fifty-one million, five hundred four thousand, one hundred thirty-three".