Base | Representation |
---|---|
bin | 10101111000001001… |
… | …111001101011001101 |
3 | 2020122002220002121101 |
4 | 111320021321223031 |
5 | 341102104313213 |
6 | 14442543103101 |
7 | 1461056431543 |
oct | 257011715315 |
9 | 66562802541 |
10 | 23490697933 |
11 | 9a6498304a |
12 | 4676ba1a91 |
13 | 22a4938281 |
14 | 11cbb41d93 |
15 | 92743bbdd |
hex | 578279acd |
23490697933 has 2 divisors, whose sum is σ = 23490697934. Its totient is φ = 23490697932.
The previous prime is 23490697859. The next prime is 23490698027. The reversal of 23490697933 is 33979609432.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 15173805124 + 8316892809 = 123182^2 + 91197^2 .
It is a cyclic number.
It is not a de Polignac number, because 23490697933 - 217 = 23490566861 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23490692933) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11745348966 + 11745348967.
It is an arithmetic number, because the mean of its divisors is an integer number (11745348967).
Almost surely, 223490697933 is an apocalyptic number.
It is an amenable number.
23490697933 is a deficient number, since it is larger than the sum of its proper divisors (1).
23490697933 is an equidigital number, since it uses as much as digits as its factorization.
23490697933 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6613488, while the sum is 55.
The spelling of 23490697933 in words is "twenty-three billion, four hundred ninety million, six hundred ninety-seven thousand, nine hundred thirty-three".
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