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235013136433 is a prime number
BaseRepresentation
bin1101101011011111011…
…1111110000000110001
3211110121110200022020021
43122313313332000301
512322301330331213
6255544043043441
722656562461655
oct3326767760061
9743543608207
10235013136433
1190739874899
1239669510581
131921419219a
14b53624aa65
1561a724bd8d
hex36b7dfe031

235013136433 has 2 divisors, whose sum is σ = 235013136434. Its totient is φ = 235013136432.

The previous prime is 235013136401. The next prime is 235013136461. The reversal of 235013136433 is 334631310532.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 179320912369 + 55692224064 = 423463^2 + 235992^2 .

It is a cyclic number.

It is not a de Polignac number, because 235013136433 - 25 = 235013136401 is a prime.

It is not a weakly prime, because it can be changed into another prime (235013137433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 117506568216 + 117506568217.

It is an arithmetic number, because the mean of its divisors is an integer number (117506568217).

Almost surely, 2235013136433 is an apocalyptic number.

It is an amenable number.

235013136433 is a deficient number, since it is larger than the sum of its proper divisors (1).

235013136433 is an equidigital number, since it uses as much as digits as its factorization.

235013136433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 58320, while the sum is 34.

Adding to 235013136433 its reverse (334631310532), we get a palindrome (569644446965).

The spelling of 235013136433 in words is "two hundred thirty-five billion, thirteen million, one hundred thirty-six thousand, four hundred thirty-three".