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23504425130413 is a prime number
BaseRepresentation
bin1010101100000100011001…
…11010010001100110101101
310002020000000210121102002101
411112002030322101212231
511040044030313133123
6121553441150455101
74644065365111243
oct526021472214655
9102200023542071
1023504425130413
117542197255187
122777394504491
1310165c4983066
145b3897d54793
152ab60d95caad
hex15608ce919ad

23504425130413 has 2 divisors, whose sum is σ = 23504425130414. Its totient is φ = 23504425130412.

The previous prime is 23504425130377. The next prime is 23504425130419. The reversal of 23504425130413 is 31403152440532.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21815457172804 + 1688967957609 = 4670702^2 + 1299603^2 .

It is a cyclic number.

It is not a de Polignac number, because 23504425130413 - 221 = 23504423033261 is a prime.

It is a super-2 number, since 2×235044251304132 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23504425130419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11752212565206 + 11752212565207.

It is an arithmetic number, because the mean of its divisors is an integer number (11752212565207).

Almost surely, 223504425130413 is an apocalyptic number.

It is an amenable number.

23504425130413 is a deficient number, since it is larger than the sum of its proper divisors (1).

23504425130413 is an equidigital number, since it uses as much as digits as its factorization.

23504425130413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 172800, while the sum is 37.

Adding to 23504425130413 its reverse (31403152440532), we get a palindrome (54907577570945).

The spelling of 23504425130413 in words is "twenty-three trillion, five hundred four billion, four hundred twenty-five million, one hundred thirty thousand, four hundred thirteen".