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23641350097 is a prime number
BaseRepresentation
bin10110000001001000…
…100101111111010001
32021000121101000112011
4112001020211333101
5341404141200342
614505524102521
71464566105641
oct260110457721
967017330464
1023641350097
11a031a20272
1246b9534a41
1322c9c04c71
141203b5a521
15935799717
hex581225fd1

23641350097 has 2 divisors, whose sum is σ = 23641350098. Its totient is φ = 23641350096.

The previous prime is 23641350053. The next prime is 23641350121. The reversal of 23641350097 is 79005314632.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22435246656 + 1206103441 = 149784^2 + 34729^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23641350097 is a prime.

It is a super-3 number, since 3×236413500973 (a number of 32 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (23641350017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11820675048 + 11820675049.

It is an arithmetic number, because the mean of its divisors is an integer number (11820675049).

Almost surely, 223641350097 is an apocalyptic number.

It is an amenable number.

23641350097 is a deficient number, since it is larger than the sum of its proper divisors (1).

23641350097 is an equidigital number, since it uses as much as digits as its factorization.

23641350097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 136080, while the sum is 40.

The spelling of 23641350097 in words is "twenty-three billion, six hundred forty-one million, three hundred fifty thousand, ninety-seven".