23753752740257 has 2 divisors, whose sum is σ = 23753752740258. Its totient is φ = 23753752740256.

The previous prime is 23753752740199. The next prime is 23753752740259. The reversal of 23753752740257 is 75204725735732.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 23467523460241 + 286229280016 = 4844329^2 + 535004^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-23753752740257 is a prime.

Together with 23753752740259, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 23753752740196 and 23753752740205.

It is not a weakly prime, because it can be changed into another prime (23753752740259) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11876876370128 + 11876876370129.

It is an arithmetic number, because the mean of its divisors is an integer number (11876876370129).

Almost surely, 2^{23753752740257} is an apocalyptic number.

It is an amenable number.

23753752740257 is a deficient number, since it is larger than the sum of its proper divisors (1).

23753752740257 is an equidigital number, since it uses as much as digits as its factorization.

23753752740257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86436000, while the sum is 59.

The spelling of 23753752740257 in words is "twenty-three trillion, seven hundred fifty-three billion, seven hundred fifty-two million, seven hundred forty thousand, two hundred fifty-seven".