Base | Representation |
---|---|
bin | 1010110100110000111011… |
… | …01001001011010110110101 |
3 | 10010021120020100200200011211 |
4 | 11122120131221023112311 |
5 | 11104442431224304432 |
6 | 122343013015401421 |
7 | 5004503431255501 |
oct | 532303551132665 |
9 | 103246210620154 |
10 | 23803206088117 |
11 | 7647979319a05 |
12 | 2805279683271 |
13 | 103882c080c61 |
14 | 5c411d20b301 |
15 | 2b42990bdd47 |
hex | 15a61da4b5b5 |
23803206088117 has 2 divisors, whose sum is σ = 23803206088118. Its totient is φ = 23803206088116.
The previous prime is 23803206088099. The next prime is 23803206088121. The reversal of 23803206088117 is 71188060230832.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 21756263538321 + 2046942549796 = 4664361^2 + 1430714^2 .
It is a cyclic number.
It is not a de Polignac number, because 23803206088117 - 219 = 23803205563829 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23803206088127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11901603044058 + 11901603044059.
It is an arithmetic number, because the mean of its divisors is an integer number (11901603044059).
Almost surely, 223803206088117 is an apocalyptic number.
It is an amenable number.
23803206088117 is a deficient number, since it is larger than the sum of its proper divisors (1).
23803206088117 is an equidigital number, since it uses as much as digits as its factorization.
23803206088117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 774144, while the sum is 49.
The spelling of 23803206088117 in words is "twenty-three trillion, eight hundred three billion, two hundred six million, eighty-eight thousand, one hundred seventeen".
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