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238149964333 is a prime number
BaseRepresentation
bin1101110111001011011…
…0000001001000101101
3211202201002011200011101
43131302312001020231
512400212342324313
6301223220123101
723130402203551
oct3356266011055
9752632150141
10238149964333
1191aa94a0046
123a1a3b36491
13195c4012c78
14b752aad861
1562dc81c5dd
hex3772d8122d

238149964333 has 2 divisors, whose sum is σ = 238149964334. Its totient is φ = 238149964332.

The previous prime is 238149964253. The next prime is 238149964343. The reversal of 238149964333 is 333469941832.

238149964333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 238141072009 + 8892324 = 487997^2 + 2982^2 .

It is a cyclic number.

It is not a de Polignac number, because 238149964333 - 217 = 238149833261 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (238149964343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 119074982166 + 119074982167.

It is an arithmetic number, because the mean of its divisors is an integer number (119074982167).

Almost surely, 2238149964333 is an apocalyptic number.

It is an amenable number.

238149964333 is a deficient number, since it is larger than the sum of its proper divisors (1).

238149964333 is an equidigital number, since it uses as much as digits as its factorization.

238149964333 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10077696, while the sum is 55.

The spelling of 238149964333 in words is "two hundred thirty-eight billion, one hundred forty-nine million, nine hundred sixty-four thousand, three hundred thirty-three".