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239848126697 is a prime number
BaseRepresentation
bin1101111101100000001…
…1111111100011101001
3211221002102120020222202
43133120003333203221
512412202110023242
6302103521425545
723220442303334
oct3373003774351
9757072506882
10239848126697
11927a0018613
123a59879b2b5
1319804a97c7a
14b87443761b
15638b95b932
hex37d80ff8e9

239848126697 has 2 divisors, whose sum is σ = 239848126698. Its totient is φ = 239848126696.

The previous prime is 239848126643. The next prime is 239848126699. The reversal of 239848126697 is 796621848932.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 236355434896 + 3492691801 = 486164^2 + 59099^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-239848126697 is a prime.

Together with 239848126699, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (239848126699) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 119924063348 + 119924063349.

It is an arithmetic number, because the mean of its divisors is an integer number (119924063349).

Almost surely, 2239848126697 is an apocalyptic number.

It is an amenable number.

239848126697 is a deficient number, since it is larger than the sum of its proper divisors (1).

239848126697 is an equidigital number, since it uses as much as digits as its factorization.

239848126697 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 62705664, while the sum is 65.

The spelling of 239848126697 in words is "two hundred thirty-nine billion, eight hundred forty-eight million, one hundred twenty-six thousand, six hundred ninety-seven".