Base | Representation |
---|---|
bin | 110110100101000100101001… |
… | …010111100010010111110111 |
3 | 1011110220210200011002212111201 |
4 | 312211010221113202113313 |
5 | 222430322231014221403 |
6 | 2210305454514113331 |
7 | 101363320352130415 |
oct | 6645045127422767 |
9 | 1143823604085451 |
10 | 240042121242103 |
11 | 6a537323613004 |
12 | 22b0993087b847 |
13 | a3c2b4b22362b |
14 | 433c15a2c62b5 |
15 | 1cb40a6b0421d |
hex | da51295e25f7 |
240042121242103 has 2 divisors, whose sum is σ = 240042121242104. Its totient is φ = 240042121242102.
The previous prime is 240042121242097. The next prime is 240042121242107. The reversal of 240042121242103 is 301242121240042.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 240042121242103 - 237 = 239904682288631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (240042121242107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120021060621051 + 120021060621052.
It is an arithmetic number, because the mean of its divisors is an integer number (120021060621052).
Almost surely, 2240042121242103 is an apocalyptic number.
240042121242103 is a deficient number, since it is larger than the sum of its proper divisors (1).
240042121242103 is an equidigital number, since it uses as much as digits as its factorization.
240042121242103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6144, while the sum is 28.
Adding to 240042121242103 its reverse (301242121240042), we get a palindrome (541284242482145).
The spelling of 240042121242103 in words is "two hundred forty trillion, forty-two billion, one hundred twenty-one million, two hundred forty-two thousand, one hundred three".
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