Base | Representation |
---|---|
bin | 10110010111010011… |
… | …001111101100011101 |
3 | 2021222112011001002122 |
4 | 112113103033230131 |
5 | 343134342203432 |
6 | 15010451032325 |
7 | 1510033116215 |
oct | 262723175435 |
9 | 67875131078 |
10 | 24013241117 |
11 | a202937518 |
12 | 47a1b9b6a5 |
13 | 2358c84218 |
14 | 123b2c5245 |
15 | 958259612 |
hex | 5974cfb1d |
24013241117 has 2 divisors, whose sum is σ = 24013241118. Its totient is φ = 24013241116.
The previous prime is 24013241101. The next prime is 24013241159. The reversal of 24013241117 is 71114231042.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 23124068356 + 889172761 = 152066^2 + 29819^2 .
It is a cyclic number.
It is not a de Polignac number, because 24013241117 - 24 = 24013241101 is a prime.
It is a super-3 number, since 3×240132411173 (a number of 32 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (24013241177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12006620558 + 12006620559.
It is an arithmetic number, because the mean of its divisors is an integer number (12006620559).
Almost surely, 224013241117 is an apocalyptic number.
It is an amenable number.
24013241117 is a deficient number, since it is larger than the sum of its proper divisors (1).
24013241117 is an equidigital number, since it uses as much as digits as its factorization.
24013241117 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 26.
Adding to 24013241117 its reverse (71114231042), we get a palindrome (95127472159).
The spelling of 24013241117 in words is "twenty-four billion, thirteen million, two hundred forty-one thousand, one hundred seventeen".
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