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240252032015117 is a prime number
BaseRepresentation
bin110110101000001000001001…
…000001100101101100001101
31011111122212111012020222201022
4312220020021001211230031
5222442242130143440432
62210550132042323525
7101414431215223403
oct6650101101455415
91144585435228638
10240252032015117
116a608350795701
1222b425534b95a5
13a4098918bbb25
144348390741473
151cb97901adb12
hexda8209065b0d

240252032015117 has 2 divisors, whose sum is σ = 240252032015118. Its totient is φ = 240252032015116.

The previous prime is 240252032015077. The next prime is 240252032015147. The reversal of 240252032015117 is 711510230252042.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 234566806949476 + 5685225065641 = 15315574^2 + 2384371^2 .

It is a cyclic number.

It is not a de Polignac number, because 240252032015117 - 224 = 240252015237901 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (240252032015147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120126016007558 + 120126016007559.

It is an arithmetic number, because the mean of its divisors is an integer number (120126016007559).

Almost surely, 2240252032015117 is an apocalyptic number.

It is an amenable number.

240252032015117 is a deficient number, since it is larger than the sum of its proper divisors (1).

240252032015117 is an equidigital number, since it uses as much as digits as its factorization.

240252032015117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 33600, while the sum is 35.

Adding to 240252032015117 its reverse (711510230252042), we get a palindrome (951762262267159).

The spelling of 240252032015117 in words is "two hundred forty trillion, two hundred fifty-two billion, thirty-two million, fifteen thousand, one hundred seventeen".