Base | Representation |
---|---|
bin | 1110000000010110001… |
… | …0101010011000001011 |
3 | 212000001121022102000121 |
4 | 3200011202222120023 |
5 | 12420232423004011 |
6 | 302311335444111 |
7 | 23245365645244 |
oct | 3400542523013 |
9 | 760047272017 |
10 | 240611141131 |
11 | 93051797659 |
12 | 3a770226637 |
13 | 198c6b9b3ba |
14 | b9078d5ccb |
15 | 63d3929e71 |
hex | 38058aa60b |
240611141131 has 2 divisors, whose sum is σ = 240611141132. Its totient is φ = 240611141130.
The previous prime is 240611141093. The next prime is 240611141137. The reversal of 240611141131 is 131141116042.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 240611141131 - 27 = 240611141003 is a prime.
It is a super-2 number, since 2×2406111411312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 240611141096 and 240611141105.
It is not a weakly prime, because it can be changed into another prime (240611141137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120305570565 + 120305570566.
It is an arithmetic number, because the mean of its divisors is an integer number (120305570566).
Almost surely, 2240611141131 is an apocalyptic number.
240611141131 is a deficient number, since it is larger than the sum of its proper divisors (1).
240611141131 is an equidigital number, since it uses as much as digits as its factorization.
240611141131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 25.
Adding to 240611141131 its reverse (131141116042), we get a palindrome (371752257173).
The spelling of 240611141131 in words is "two hundred forty billion, six hundred eleven million, one hundred forty-one thousand, one hundred thirty-one".
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