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241005134513309 is a prime number
BaseRepresentation
bin110110110011000101100001…
…011011101000010010011101
31011121022212101012110210111112
4312303011201123220102131
5223042112003413411214
62212324121430431405
7101523021621644045
oct6663054133502235
91147285335423445
10241005134513309
116a878781495141
12230444abb02565
13a4628c07b991a
1443729d4420725
151cce16b199a3e
hexdb31616e849d

241005134513309 has 2 divisors, whose sum is σ = 241005134513310. Its totient is φ = 241005134513308.

The previous prime is 241005134513281. The next prime is 241005134513317. The reversal of 241005134513309 is 903315431500142.

241005134513309 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 237369332172025 + 3635802341284 = 15406795^2 + 1906778^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-241005134513309 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (241005134513369) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120502567256654 + 120502567256655.

It is an arithmetic number, because the mean of its divisors is an integer number (120502567256655).

Almost surely, 2241005134513309 is an apocalyptic number.

It is an amenable number.

241005134513309 is a deficient number, since it is larger than the sum of its proper divisors (1).

241005134513309 is an equidigital number, since it uses as much as digits as its factorization.

241005134513309 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 194400, while the sum is 41.

The spelling of 241005134513309 in words is "two hundred forty-one trillion, five billion, one hundred thirty-four million, five hundred thirteen thousand, three hundred nine".