241005224415133 has 2 divisors, whose sum is σ = 241005224415134. Its totient is φ = 241005224415132.

The previous prime is 241005224415121. The next prime is 241005224415149. The reversal of 241005224415133 is 331514422500142.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 225962136369369 + 15043088045764 = 15032037^2 + 3878542^2 .

It is a cyclic number.

It is not a de Polignac number, because 241005224415133 - 2²⁵ = 241005190860701 is a prime.

It is a super-4 number, since 4×241005224415133⁴ (a number of 59 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 241005224415092 and 241005224415101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (241005224415833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120502612207566 + 120502612207567.

It is an arithmetic number, because the mean of its divisors is an integer number (120502612207567).

Almost surely, 2^{241005224415133} is an apocalyptic number.

It is an amenable number.

241005224415133 is a deficient number, since it is larger than the sum of its proper divisors (1).

241005224415133 is an equidigital number, since it uses as much as digits as its factorization.

241005224415133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 115200, while the sum is 37.

Adding to 241005224415133 its reverse (331514422500142), we get a palindrome (572519646915275).

The spelling of 241005224415133 in words is "two hundred forty-one trillion, five billion, two hundred twenty-four million, four hundred fifteen thousand, one hundred thirty-three".