Base | Representation |
---|---|
bin | 110110110011001011000110… |
… | …110110100100010101111111 |
3 | 1011121100102212002222222021022 |
4 | 312303023012312210111333 |
5 | 223042211244021304101 |
6 | 2212330552441054355 |
7 | 101523323334411362 |
oct | 6663130666442577 |
9 | 1147312762888238 |
10 | 241011131041151 |
11 | 6a880279364279 |
12 | 230456a41873bb |
13 | a463337c3b153 |
14 | 43730029a80d9 |
15 | 1cce3bc848a1b |
hex | db32c6da457f |
241011131041151 has 2 divisors, whose sum is σ = 241011131041152. Its totient is φ = 241011131041150.
The previous prime is 241011131041141. The next prime is 241011131041169. The reversal of 241011131041151 is 151140131110142.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-241011131041151 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 241011131041151.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (241011131041141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120505565520575 + 120505565520576.
It is an arithmetic number, because the mean of its divisors is an integer number (120505565520576).
Almost surely, 2241011131041151 is an apocalyptic number.
241011131041151 is a deficient number, since it is larger than the sum of its proper divisors (1).
241011131041151 is an equidigital number, since it uses as much as digits as its factorization.
241011131041151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 480, while the sum is 26.
Adding to 241011131041151 its reverse (151140131110142), we get a palindrome (392151262151293).
The spelling of 241011131041151 in words is "two hundred forty-one trillion, eleven billion, one hundred thirty-one million, forty-one thousand, one hundred fifty-one".
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