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241030212315281 is a prime number
BaseRepresentation
bin110110110011011100111000…
…001011110110100010010001
31011121102021002220210010112222
4312303130320023312202101
5223043014333323042111
62212343430111030425
7101524600232515244
oct6663347013664221
91147367086703488
10241030212315281
116a888380230a14
122304932a50b415
13a465089193bbc
144373cd2c5b25b
151cceb37ad97db
hexdb37382f6891

241030212315281 has 2 divisors, whose sum is σ = 241030212315282. Its totient is φ = 241030212315280.

The previous prime is 241030212315241. The next prime is 241030212315283. The reversal of 241030212315281 is 182513212030142.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 235026805781056 + 6003406534225 = 15330584^2 + 2450185^2 .

It is a cyclic number.

It is not a de Polignac number, because 241030212315281 - 210 = 241030212314257 is a prime.

It is a super-2 number, since 2×2410302123152812 (a number of 30 digits) contains 22 as substring.

Together with 241030212315283, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (241030212315283) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120515106157640 + 120515106157641.

It is an arithmetic number, because the mean of its divisors is an integer number (120515106157641).

Almost surely, 2241030212315281 is an apocalyptic number.

It is an amenable number.

241030212315281 is a deficient number, since it is larger than the sum of its proper divisors (1).

241030212315281 is an equidigital number, since it uses as much as digits as its factorization.

241030212315281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23040, while the sum is 35.

The spelling of 241030212315281 in words is "two hundred forty-one trillion, thirty billion, two hundred twelve million, three hundred fifteen thousand, two hundred eighty-one".