2411000113 has 2 divisors, whose sum is σ = 2411000114. Its totient is φ = 2411000112.

The previous prime is 2411000099. The next prime is 2411000147. The reversal of 2411000113 is 3110001142.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2045119729 + 365880384 = 45223^2 + 19128^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2411000113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2411000093 and 2411000102.

It is not a weakly prime, because it can be changed into another prime (2411001113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1205500056 + 1205500057.

It is an arithmetic number, because the mean of its divisors is an integer number (1205500057).

Almost surely, 2^2411000113 is an apocalyptic number.

It is an amenable number.

2411000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2411000113 is an equidigital number, since it uses as much as digits as its factorization.

2411000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 2411000113 is about 49101.9359394311. The cubic root of 2411000113 is about 1340.9082935624.

Adding to 2411000113 its reverse (3110001142), we get a palindrome (5521001255).

The spelling of 2411000113 in words is "two billion, four hundred eleven million, one hundred thirteen", and thus it is an aban number.